hitung pH larutan 0,10 M asam asetat apabila diketahui harga Ka asam asetat 1,75×10^-5
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Pertanyaan
hitung pH larutan 0,10 M asam asetat apabila diketahui harga Ka asam asetat 1,75×10^-5
1 Jawaban
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1. Jawaban Raa21299
Diketahui:
M CH3COOH = 0,1 M
Ka CH3COOH = 1,75x10^-5
Ditanya : pH?
Jawab:
[H+] = √Ka x Ma
[H+] = √1,75x10^-5 . 10^-1
[H+] = √1,75x10^-6
[H+] = 1,32x10^-3
pH = -log[H+]
pH = -log 1,32x10^-3
pH = 3-log1,32
Semoga membantu.