bentuk yang setara dengan 2√2 ——— 6-3√3

Kelas 9 Matematika
Bab Akar dan Pangkat

(2 √2) / (6 - 3√3)
= (2 √2)/(6 - 3√3) . (6 + 3√3)/(6 + 3√3)
= (12√2 + 6√6) / (6² - (3√3)²)
= (12√2 + 6√6) / (36 - 27)
= (4√2 + 2√6)/3

[tex] \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } \\ = \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } \times \frac{6 + 3 \sqrt{3} }{6 + 3 \sqrt{3} } \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{36 + 18 \sqrt{3} - 18 \sqrt{3} - 9 \times 3 } \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{36 - 27} \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{9} \\ = \frac{4 \sqrt{2} + 2 \sqrt{6} }{3} [/tex]