dik＝298°k,dit＝°c,°f,°r

[tex] {c}^{o} = 298 - 273 = {25}^{o} [/tex]
[tex] {f}^{o} = ( \frac{9}{5} x {25}^{o} ) + {32}^{o} \\ {f}^{o} = {77}^{o} [/tex]
[tex] {r}^{o} = \frac{4}{5} x {25}^{o} \\ {r}^{o} = {20}^{o} [/tex]