Hitunglah ph larutan HBRO 0_001 M(KA=4×10-9)

Diketahui :
M HBr = 0,001
Ka = 4x10^-9
Ditanya :
Jawab :
[H+] = √Ka x Ma
[H+] = √4x10^-9 • 10^-3
[H+] = √4x10^-12
[H+] = 2 x 10^-6
pH = -log[H+]
pH = -log 2x10^-6
pH = 6-log2

Semoga membantu.