Berapa kah nilai x dari (1/16)pangkat x-2 = 4

(1/16)^(x - 2) = 4
(4^-2)^(x - 2) = 4^1
-2(x - 2) = 1
-2x + 4 = 1
-2x = 1 - 4
x = -3/-2
x = 3/2

[tex]( \frac{1}{16}) {}^{x - 2} = 4 \\ (4 {}^{ - 2} ) {}^{x - 2 } =4 \\ dibagi.... \\ - 2(x - 2) = 1 \\ - 2x + 4 = 1 \\ - 2x = 1 - 4 \\ - 2x = - 3 \\ x = \frac{ - 3}{ - 2} \\ x = \frac{3}{2} \\ \\ semoga \: membantu.......[/tex]
good luck.....