1. (2-³)^-4= 2. (6y)^5 : (3y)^4= 3. 32 3/2=
Matematika
arandaum
Pertanyaan
1. (2-³)^-4=
2. (6y)^5 : (3y)^4=
3. 32 3/2=
2. (6y)^5 : (3y)^4=
3. 32 3/2=
1 Jawaban
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1. Jawaban indahkim1
[tex] ({2}^{ - 3}) {}^{ - 4} = {2}^{( - 3 \times - 4)} \\ = {2}^{12} [/tex]
[tex] \frac{ {6y}^{5} }{ {3y}^{4} } \\ = 2 {y}^{5 - 4} \\ = 2y[/tex]
[tex]32 \frac{3}{2} \\ = \frac{67}{2} \\ = 33 \frac{1}{2} \: atau \: 33.5[/tex]