harga 1 pasta gigi dan 4 sabun rp.14.000 sedangkan harga 2 pasta gigi dan 1 sabun rp.10.500 harga 2 pasta gigi dan 6 sabun brapa

misal pasta gigi =x
sabun = y

x + 4y = 14000
x= 14000- 4y


2x + y = 10500
2 (14000-4y) + y = 10500
28000 - 8 y + y = 10500
-7 y = 10500-28000
-7 y = - 17 500
y = 2500

x = 14000- 4( 2500)
x = 14000- 10000= 4000

harga 2 pasta gigi + 6 sabun = 2(4000) + 6 (2500) = 8000+15000=23000

Jawab :

Misal : pasta gigi = x
sabun = y

2x + 8y = 28.000
2x + 2y = 10.500
__________________-
6y = 17.500
y = 17.500/6
y = 2.916

Subst ke 1

x + 4y = 14.000
x + 4(2.916) = 14.000
x + 11.664 = 14.000
x = 2.336

Harga 2 pasta gigi dan 6 sabun

= 2(2.336) + 6(2.916)
= 4.672 + 17.496
= 22.168