nilai x yg memenuhi persamaan 1/2log(x2 [tex] \frac{1}{2 } log( {x2} - 3) - \frac{1}{2} log \: x = - 1 [/tex]

LogAritMa

(1/2)'log (x² - 3) - (1/2)'log x = -1

(1/2)'log ((x² - 3)/x) = -1

(x² - 3)/x = (1/2)^-1

(x² - 3)/x = 2

kali silang

x² - 3 = 2x

x² - 2x - 3 = 0

(x - 3)(x + 1) = 0

x = 3 ; x = -1

Syarat numerus : > 0
x > 0
x² - 3 > 0 ---> x² > 3

NiLai x yg memenuhi :
x = 3

#asumsi (1/2) adalah basis