Diketahui fungsi f dan g yg ditentukan oleh f(x) = 5x + 1 dan g(x) = 2x - 1/x + 1. Nilai dari ( f/g ) (2)

a) (f o g)(x) = f(g(x))
= f((2x + 1)/(3x + 4))
= ((2x + 1)/(3x + 4)) + 3
= ((2x + 1) + 3(3x + 4))/(3x + 4)
= (11x + 13)/(3x + 4)

b) (f o g)(x) = 2x² - 6x - 1
f(x² - 3x +1) = 2(x² - 3x + 1) - 3
f(x) = 2x - 3

c) f(x - 2) = (x - 2)/(2x - 3)
f(x - 2) = (x - 2)/(2(x - 2) + 1)
f(x) = x/(2x + 1)
y = x/(2x + 1)
2xy + y = 2x
2xy - 2x = -y
x(2y - 2) = -y
x = -y/(2y - 2)
f^-1 (x) = -x/(2x - 2) keterangan: f^-1 (x) = invers dr f(x)
maka:
f^-1(3x + 1) = -(3x + 1)/(2(3x + 1) + 1)
= (-3x - 1)/(6x + 3)