larutan 100 ml asam sulfat (H2so4) 0,05 m mempunyai harga ph sebesar?

ph =- log [ H+]

[ H+] = val.Asam x M
[ H+] =2 x 5.10^-2
[ H+] =10^-1

ph =- log (10^-1)
ph = 1

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