Matematika

Pertanyaan

1. Diketahui f(x) = 2x+1
(Gof)(x) = 2x²+6x+2
Tentukan g(3)...
2. Diketahui f(x) = 2x+1 per x-3 ; x tidak sama dengan 0
Tentukan
a. F pangkat -1(x)
b. F pangkat -1(9)
Pliss bantu jawab kak

1 Jawaban

  • 1) f (x) = 2x +1
    gof(x) = 2x^2 + 6x + 2
    g { f (x) } = 2x^2 + 6x + 2
    g ( 2x+1) = 2x^2+ 6x +2
    g (2x+1) = 1/2(2x+1)^2+ 4x + 3/2
    g (2x+1) = 1/2(2x+1)^2 + 2(2x+1) -1/2
    g (x) = 1/2x^2 +2x -1/2
    g (3) = 1/2(3)^2 +2.3 -1/2
    = 9/2 +6 -1/2
    = 10
    2)f (x) = (2x+1)/(x-3)
    y = (2x+1)/(x-3)
    (x-3)y = 2x +1
    xy -3y = 2x + 1
    xy -2x = 3y +1
    (y -2)x = 3y +1
    x = (3y +1)/(y -2)
    f-1(x) = (3x +1)/(x -2)
    f-1(9) = (3.9 +1)/(9-2)
    = 28/7
    = 4

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