Berapa ph larutan campuran dari 250 ml HNO3=0,1 250 ml air

M1. M1= M2. V2
0,1.0,25 = M2. 0.5
1/40 = M2. 0.5
2/40 = M2
0.05 = M2
5.10^-2 = M2

HNO3 >>Asam kuat

[H+] = x [M asam]
[H+] = 1.[5.10^-2]
[H+] = 5.10^-2

pH = 2-log 5