hitunglah massa H2SO4 yang mempunyai PH = 12 dan v = 500ml

pH = 12
[H+] =
[tex] {10}^{ - 12} [/tex]
[H+] = val x M
[tex] {10}^{ - 12} = 1 \times M[/tex]
M =
[tex] {10}^{ - 12} [/tex]
[tex]M = \frac{g}{Mr} \times \frac{1000}{ml} [/tex]
[tex] {10}^{ - 12} = \frac{g}{98} \times \frac{1000}{500} [/tex]
[tex]g = 49 \times {10}^{ - 12} gram[/tex]
maaf kalau salah